Recent content by livio

thanks :) this is getting far too complicated than I thought.... I hope not. I think what I need is a simple equation to estimate the drop in voltage. this obviously depends on water resistivity too (this can be estimated around 5 kOhm/cm). thank you for noting the incongruency of the distance...

since I do not know the actual pole distance but only the size of the container of the dipole (15 cm) I followed the suggestion to model it using a 2 point charge dipole (and I think this is accurate).

it means there is a dipole, underwater, it can be modeled as two point charges separated 15 cm apart. an average of 5 mV voltage can be measured in close proximity to it. The voltage will drop with distance. I need to estimate the drop. see the sketch in the previous comments.

the measurement should not be on the midline necessarily either. let's say the reading is variable around the dipole (the absolute voltage reading) but on average is around 5 mV. I would need to take that 5 and calculate the drop for increased distances. let's consider 5 mV the reading at an X...

I hope this helps. I have modeled the dipole as you suggested using two point sources placed 15 cm apart. This would be "container", in reality the poles are probably much closer inside. I have placed the reference ground at 2 meters. I have a reading at distance 0 and need the other ones. The...

what I know is that close contact readings on the dipole surface are between 2 and 20 mV with an average of 5 mV. Ignore the statement of the measurement "across" the dipole, that was an estimate of mine from another model. Sorry for the confusion. The problem is that whatever equation I am...

you are right, thank you for noting that. I can't measure at x>d/2. I only have an average measurement "along" the dipole and this is 5mV. If with net potential you mean the voltage measured across the dipole and not referenced to the a distant reference electrode, this should be around 1-2 mV...

my problem is to calculate the voltage drop at different distances ( even along 1 direction only) given a known value at 0 cm (so touching the dipole)

biologist here :)

thank you. so just to make sure I understood: using the voltage the decay is with distance square, using the field the decay is with the cube ? is the field the first derivative of the voltage over space? regardless of this, I basically resolve it for r = 0 and obtain p, then use the same value...

Thank you Berkeman :) the reference far away is because the reading of 5 mV was taken in this way (not by me) so I am just reporting. I guess what is relevant is that the measuring electrode is not in "differential mode" but is referred to some ground far away, enough not to be affected by the...

If I resolve the equation in 0, imposing a voltage value of 5 mV, it gives a non real solution, therefore I cannot resolve it for R=1 because I do not know which voltage value to impose. I am sure this is simpler than I am putting it :) thanks for any advice!