Recent content by Loadme

Where I am stuck is how to transform the right part as to write it for the proper laplace transform How I would do it(and correct me where I am wrong) y'' + 4y = x[u(x-0)-u(x-π)] + πe^(-x)*u(x-π) How do you apply the Heavyside? Can you explain me your technique?

I have a differential equation that has to be solved with Laplace. I wish someone can provide a full answer y'' + 4y = x , 0<=x<π y'' + 4y = πe^-x , π<=x Initial Conditions: y(0)=0 y'(0)=1

x(dz/dx)-3xz = -3x² how did you find that?

Thank you a lot. One more question: In ODE I reach in a place where i have that \frac{dz}{dx}*x^3- 3x^2*z + 3x^4 = 0 I cannot find the derivatve on that

\frac{dy}{dx} - \frac{1}{x}*y + \frac{1}{y^2}*x = 0 This is a bernoulli differential equation which follows the following procedure http://en.wikipedia.org/wiki/Bernoulli_differential_equation Can someone provide the full steps because somewhere I am mistaken?