Recent content by lohboys

  1. lohboys

    Engineering Derivation of Thermodynamic Relations

    dG= -SdT + VdP ... now dividing by dV holding temperature constant (dG/dV)T = -S (dT/dV)T + V (dP/dV)T ... now dT and constant temperature cancel out final answer: (dG/dV)T = V (dP/dV)T