Recent content by loisNominator
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Proving Trigonometric Identities: Attempt and Solution
It turns out that it was a typo. It should read: 1 - \frac{\sin^2 t}{1 + \cot t} - \frac{\cos^2 t}{1+\tan t} = \sin t \cos t Solution is straightforward.- loisNominator
- Post #6
- Forum: Precalculus Mathematics Homework Help
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Proving Trigonometric Identities: Attempt and Solution
So it appears. Let me go back to the person who set the original problem. Sorry!- loisNominator
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Proving Trigonometric Identities: Attempt and Solution
The first two terms simplify to cos t, but I'm still having the same issue wrt further simplification. One version has me stuck at: cos t (cos t + sin t - cos^2 t)/(cos t + sin t) I'd appreciate another hint. Thanks.- loisNominator
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Proving Trigonometric Identities: Attempt and Solution
Homework Statement I'm attempting to prove that 1 - sin^2 t /(1 + cos t) - cos^2/(1+tan t) = cos t sin t 2. The attempt at a solution I've tried various approaches. The most promising has the LHS reduced to: (sin t cos t (1 + cos t + sin t cos t))/((1 + cos t)(cos t + sin t))...- loisNominator
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- Identity Trigonometric Trigonometric identity
- Replies: 5
- Forum: Precalculus Mathematics Homework Help