Recent content by lordWilhelm

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    Undergrad Where does the 1/2 coefficient come from in v·dv/dt = 1/2 d(v²)/dt?

    OK, this has been bugging me for a while. Why is it that \mathbf{v} \cdot \frac{d \mathbf{v}}{d t} = 1/2 v^2 where regular v is just the magnitude of bold v or more specifically where does the 1/2 coefficient turn up.
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