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lordWilhelm
Recent content by lordWilhelm
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Dot Product: Explaining 1/2 Coefficient
OK, this has been bugging me for a while. Why is it that \mathbf{v} \cdot \frac{d \mathbf{v}}{d t} = 1/2 v^2 where regular v is just the magnitude of bold v or more specifically where does the 1/2 coefficient turn up.
lordWilhelm
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Feb 16, 2010
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Replies: 2
Forum:
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