Recent content by lordWilhelm
-
L
Undergrad Dot Product: Explaining 1/2 Coefficient
OK, this has been bugging me for a while. Why is it that \mathbf{v} \cdot \frac{d \mathbf{v}}{d t} = 1/2 v^2 where regular v is just the magnitude of bold v or more specifically where does the 1/2 coefficient turn up.- lordWilhelm
- Thread
- Dot Dot product Product
- Replies: 2
- Forum: Calculus