Oh nooo I can't believe it was that simple, I have been trying to calculate it as a acute and obtuse angle (hence my issues). The time when you are doing maths and you start to bash your head against a brick wall, only to realize that the answer was right in front of you lol. Thank you...
[QUOTE Since $\overline{AD}\parallel\overline{BC}$, and the trapezoid is cyclic, we know it must be isosceles. So we know $\angle A=60^{\circ}$, if $\measuredangle C=120^{\circ}$.
I had changed the original degrees and didn't realize I had changed the triangles to equal sides. My triangles are...
Sorry don't have an equation, my wording mistake, just trying to calculate the angle of E and F. What I have worked out is the angles of A, B, C, and D. A=70 B=110 C=120 D=60. But have no idea how to calculate E and F. If I turn C and D into a right angle on the outside of the trapezoid I get...
I have the above equation to try and complete and I have no idea how to do it I have worked out all the angles for A, B, C, and D accept the ones within the diagonal line E and F. Any hints?