The question is something like this, find the:
d/dx of sin-1 (X+a) /b.
then evaluate,
intergarte of X / (9-4x-x2) 1/2
&
intergarte of X2 / (9-4x-x2) 1/2
What i get for the first part is,
d/dx of sin-1 (X+a) /b = 1 / ( -X2/b2-2aX/b2-a2+b2/b2)1/2
Then I'm stuck. xD
Sorry for the...