Recent content by mac227

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    Easy Unit Conversions: How to Convert Kilojoules to Gallons

    unit conversions!help! Homework Statement How do I convert Kilojoules to gallons? Homework Equations KJ to J to kg to g to L to gal The Attempt at a Solution I have 2.258 KJ (1000J/1) 2258 Joules. I am stuck here. How do i get from Joules to kilograms??
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    Centripetal force and satellite

    Homework Statement If a satellite drops to a lower orbit, how does this affect its centripetal force, period, tangential speed, and angular velocity? Homework Equations Fc=m(v2/r) The Attempt at a Solution Because of the formula above, the satellite experiences an increase in Fc...
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    What is the angle of the velocity vector of a released package?

    solve for the vy going up or down? v_x is the same as v_ox because a_x = 0 correct? v_x = 26.68 v_y= 0 at peak... calculate v_y coming down??
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    How Fast Must a Tennis Player Run to Return a Lob?

    projectile problem help! Homework Statement The lob in tennis is an effective tactic when your opponent is near the net. It consists of lofting the ball over his head, forcing him to move quickly away from the net (see the drawing). Suppose that you loft the ball with an initial speed of...
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    What is the angle of the velocity vector of a released package?

    because i was calculating the velocity in the y direction of the package being dropped. WHen the plane reaches 906m it drops a package. So that packages initial velocity is 0. voy=0 So to get theta you used tan(theta) = v_y / v_x ? did you get 26.68 for vx and how would you go about...
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    What Angles Will Hit a 91.4m Target with a 596 m/s Bullet?

    you lost me here sec^2(θ) ? does this mean sec(θ) 2 ?
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    What is the angle of the velocity vector of a released package?

    Homework Statement An airplane with a speed of 96.8 m/s is climbing upward at an angle of 74.0 ° with respect to the horizontal. When the plane's altitude is 906 m, the pilot releases a package. (a) Calculate the distance along the ground, measured from a point directly beneath the point of...
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    What Angles Will Hit a 91.4m Target with a 596 m/s Bullet?

    i plugged v_{oy}=v_o sin\theta and (vy-voy)/ay= t into vy=voy+(ay)t to get: vy=voysin(theta)+ay(vy-voy/ay) sin`-1 * ((vy-ay(vy-voy/ay))/voy)=theta
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    What Angles Will Hit a 91.4m Target with a 596 m/s Bullet?

    we know that the velocity of the ball is also 0 at its peak and when it comes to rest... So a=-9.8 v=0 and v0y=? when calculating the ball's rise to its peak. On its way down voy=0 and vy=? a=9.8 I have trouble seeing how to use (vy-voy)/ay= t too many unknowns?
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    What Angles Will Hit a 91.4m Target with a 596 m/s Bullet?

    So an equation without the y distance or y units altogether? vy=voy+(ay)t (vy-voy)/ay= t
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    What Angles Will Hit a 91.4m Target with a 596 m/s Bullet?

    first equation: x/(v_o cos\theta)= t Second equation: y=voysinθt+.5(-9.8)t2 y=voysinθt + -4.9t2 cancel out the t's ? ( y-voy sinθ ) / -4.9 = t ...??
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    What Angles Will Hit a 91.4m Target with a 596 m/s Bullet?

    ok so then x=vo(cosθ)(t)+.5(a)t`2 cosθ=.5(a)t/x θ=cos`-1(.5at/x) ? not sure about what to do with cos
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    What Angles Will Hit a 91.4m Target with a 596 m/s Bullet?

    x=vo(t)+.5(a)t2 so, 91.4=596(t) + .5(0)t2 which becomes 91.4=596(t) t=0.153s not sure what you mean by solve for t in terms of theta?
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    What Angles Will Hit a 91.4m Target with a 596 m/s Bullet?

    "OK. You're right that you need to start off calculating the time it takes to reach peak. Try this: Can you calculate the time it takes to travel all 91.4m in the x direction? If so, can you find the time at the peak? If so, you can plug your result for t_peak into the equation for the y...
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    What Angles Will Hit a 91.4m Target with a 596 m/s Bullet?

    Homework Statement The drawing shows an exaggerated view of a rifle that has been ‘sighted in' for a 91.4-meter target. If the muzzle speed of the bullet is v0 = 596 m/s, there are the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the...