Recent content by Mac5214

oh okay yes i do, its because cosine is the adjacent over the hypotenuse which is the total magnitude (4). Thank you for helping me realize that.

Okay so I may have got a answer, but I didn’t use any kinematic equations so I’m not sure if it is correct or not, I realized that the horizontal component of velocity is constant, so when the projectile is at the maximum height, the vertical component of velocity will be equal to 0 therefore...

1. the question is this: a projectile's speed at launch is four times its speed at the top of the trajectory. What is the launch angle? I am given no numerical values, but from my understanding gravity is a constant 9.8, and at the maximum height velocity should be equal to 0. 2.the equation...

Hi! my name is Matthias and i am currently in undergrad for a physical therapy degree. my forte is however not physics and so i am struggling a lot. my class is totally experimental based and we don't really have a book or problems in class to go off of for most of our homework's so i thought...