Recent content by manrkin

Thank you Chet! I really appreciate your help. It took me three cups of tea and some serious head scratching. I will come back to you on solving it using the moments, however for now I'm currently half way through a rather large assignment and I'm going to keep on plugging away. Kind regards...

So i think I have it... The x component of T1 is T1cos30 and the x component of T2 is t2cos60 And T1x - T2x = 0 the y component of T1 is t1sin30 and the y component of t2 is t2sin60 and t1y+t2y-500=0 so if T1cos30-T2cos60=0 then T1cos30=T2cos60 therefore T1 = T2cos60/cos30...

But now I'm not sure where to go with this information. Am I missing something important?

And T1y + T2y must equal 0.50 kN?

And T1y component will equal half of T1?

For T2 X component it will equal half of t2 correct?

Force balances? How do I work them out?

Ok, would first divide the total weight of the girder by the number of cables, so each cable would be experiencing an equal force?

Homework Statement There is a girder hanging from a crane by two cables. The girder is 2.6m long and hanging at an angle. The weight of the girder is 0.50 kN. Calculate the tensions of each cable. Homework EquationsThe Attempt at a Solution I would divide the two cables into their x and y...