Recent content by marsupialofdeath

Yeah, the first part of the question asked for the moment about the axis, which is what those angles were used for. So we need to manipulate the force vector so that instead of the given angles, it's in the x-z plane. So can we set it up so that Fx = 30cos(α) and Fz = 30cos(γ) = 30sin(α)? From...

It's kind of hard to see in the diagram, but F is 60° from both the x and y axes. Fx = F*cos(α) = 30*cos(60°) = 15 N Fy = F*cos(β) = 30*cos(60°) = 15 N Fz = F*cos(γ) = 30*cos(45°) ≈ 21.21 N So, the vector for F should be (15i + 15j + 21.21k) N And the vector for r is (-0.1i + 0.15k) m So, r×F...

Homework Statement Calculating the moment of force F about the axis isn't hard; how do I determine how to produce the maximum moment? Homework Equations Maxis = ûaxis ⋅ (r×F) F = 30N (This doesn't change at all during the problem) The Attempt at a Solution I would guess that since the...