Recent content by Martin Hanna

thank you very much

because there is a formula which says that N(Refractive index) = 1/ sin C(48) oh i see yeah I am suppose to sin the 48

well it makes sense because the answer is 48 and 48 is the critical angle of air-water boundary so now i find the refractive index 1/48

therefore c must be 180-(42+90)

42 ? i doubt you can just determine it from looking at the diagram as the question asks to calculate it

so there fore the angle of incidence is 90 so that means C would be a critical angle

that would be 90 ?

Thanks for responding but i am trying but can't figure it out its probably right there in my face but i just can't see it yet

Can someone help me in solving this question ? my attemp is sin42/sin 90 to get the refractive index then n =sin i/sin r to get c and for b n=1/sinc