Recent content by marutkpadhy
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MHB Area of 'that' part of the circle ....
Integrating ( \sqrt{16-x^2} - \sqrt{6x} ), lower limit = 0, upper limit = 2 right? then doubling the answer, + \pi r^2 / 2 = 8- marutkpadhy
- Post #10
- Forum: Calculus
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MHB Area of 'that' part of the circle ....
By Integrating, f(x) - g(x) where these two functions are of the curves. Now? Please guide me the whole solution.- marutkpadhy
- Post #7
- Forum: Calculus
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MHB Area of 'that' part of the circle ....
x = 2 or -8, discarding -8, we have only solution for x = 2. now?- marutkpadhy
- Post #5
- Forum: Calculus
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MHB Area of 'that' part of the circle ....
No :/ I am very new to this topic, I am learning. I would appreciate if you could give the detailed solution, please. :) Also, I am very confused with this LaTeX system, and expressing mathematics on web. :(- marutkpadhy
- Post #3
- Forum: Calculus
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MHB Calculating Radius of Circular Section from Sphere and Plane Intersection
Find the radius of the circular section of the sphere of the sphere x^2 + y^2 + z^2 = 49 by the plane 2x+3y-z-5 \sqrt{14}= 0- marutkpadhy
- Thread
- Circular Radius Section
- Replies: 2
- Forum: Differential Geometry
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MHB Area of 'that' part of the circle ....
Using integral find the area of that part of the circle x^2 + y^2 = 16 which is exterior to the parabola y^2 = 6x.- marutkpadhy
- Thread
- Area Circle
- Replies: 10
- Forum: Calculus
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MHB Cost Functions for a Firm: Marginal & Average Cost
The cost function of a firm is given by C(x) = 300x - 10x^2 - 1/3x^3. A) Find the Marginal Cost Function B) Average cost function C) The output at which marginal cost is equal to average cost.- marutkpadhy
- Thread
- Average Functions Marginal
- Replies: 1
- Forum: Calculus
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MHB Maximum light through the window
A window is in the form of rectangle surmounted by a semi circle. The total perimeter of the window is 10m. Find the dimensions of the window to admit maximum light through the whole opening.- marutkpadhy
- Thread
- Light Maximum Window
- Replies: 3
- Forum: Calculus