Recent content by Masgr404
-
M
Analyzing a Smooth Curve for -π < t < π
The function is not continuous at that particular point that makes the denominator go to zero. Perhaps we could rewrite in the complex plane?- Masgr404
- Post #3
- Forum: Calculus and Beyond Homework Help
-
M
Analyzing a Smooth Curve for -π < t < π
Homework Statement Determine where r(t) is a smooth curve for -pi <t<pi R(t)= (x(t),y(t))=(4sin^3(t), 4cos^3(t)) Homework Equations The Attempt at a Solution To be honest I have no idea where to start. I know what a smooth function is but my understanding is that the sin(t) and...- Masgr404
- Thread
- Curve Smooth
- Replies: 4
- Forum: Calculus and Beyond Homework Help