Recent content by Math_312 46

  1. M

    MHB How do I find the average of two averages?

    Ah, I see now. So the answer is then 10,6?
  2. M

    MHB How do I calculate the amount from the volume?

    Thank you so much, you are a lifesaver:love: I don't want to sound annoying, but when I was trying to solve another difficult task, I was stuck on how to figure out the lineup itself. 10.2 n + 10.8 2n / n + 2n Question: In a survey, several measurements were taken and the average of the...
  3. M

    MHB How do I calculate the amount from the volume?

    So to be sure the answer is 6500 m^2 of the whole question?
  4. M

    MHB How do I calculate the amount from the volume?

    Ah, I see. so if I convert 6.5 e 21 nm² to m², which then becomes 65000 m². Is this the answer or is something wrong?
  5. M

    MHB How do I find the average of two averages?

    Is it then 7 or 15,9?
  6. M

    MHB How do I calculate the amount from the volume?

    Sorry in advance but I find maths very difficult. But according to my calculations based on your explanation, it came out like this: 6.5 x 10^23 / 100 = 65 e 21 (65 and 21 zeros) And thus I get the answer that 65 e 21nm² can the gold leaf of a gold bar cover?
  7. M

    MHB How do I calculate the amount from the volume?

    Is the answer 0,01m^2? If this is wrong can you help me?
  8. M

    MHB How do I find the average of two averages?

    So if I do this calculation, the answer is 21?
  9. M

    MHB How do I find the average of two averages?

    Are you suggesting that I do this: 10.2 n / n = 10.2 or have I misunderstood you?
  10. M

    MHB How do I calculate the amount from the volume?

    The gold pavilion in the city of Kyoto is covered with gold leaf. Gold leaf has a thickness of 100 nm (nanometres) and is made from gold bars. A gold bar has a volume of 0.65 dm^3. How many square metres can the gold leaf from a gold bar cover?
  11. M

    MHB How do I find the average of two averages?

    In a statistical study, several measurements were taken and the average value of the measurements was 10.2. In a new survey, twice as many measurements were taken and the mean of these measurements was 10.8. What is the mean of all the measurements?
Back
Top