Recent content by mathew350z

  1. M

    How can Simpson's Rule have a large margin of error?

    Yes, I understand that tan(pi/2) diverges but I still am having a little trouble as to why that Simpson's Rule over-estimates the actual answer.
  2. M

    How can Simpson's Rule have a large margin of error?

    \int tan(x)dx with the limits of 0 to 1.55, with n=10. Using Simpson's Rule, my answer was 4.923651704. But I don't understand why Simpson's Rule varies from my calculator's answer (TI-84 Plus) which is 3.873050987. I thought the higher N with Simpson's Rule would make your answer even more...
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