Recent content by Mathysics29

This is what I got for 25! 2^22 × 3^10 × 5^6 × 7^3 × 11^2 × 13 × 17 × 19 × 23

How did you do the arithmetic for 1000! I sorry I really have no clue.

It's not homework. It's from a local mathematics competition for high school students. How can your write every factor of 25 factorial. Even if you write for 5 hours you still won't get close. I suspects using combinations though I'm not smart enough to work that out myself.

Yes but I can't wrap my head around the question because the number is huge. It's litterally 25! How can I use prime factorization...?

Let n=1×2×3×...×25 If a positive factor of n is chosen at random, what is the probability that the chosen factor is an odd number?At first I thought of listing out the factors like you would for 1×2×3×4×5 for example. Which is in this case {1,2,3,6,8,10,12,15,20,40,60,120} but it is way too many...

Can I say this 40 Summation (√2n-√(2n)^(2)-1)) n=1 And how can I find the partial sum for this

Convering series? But how can I estimate the final and?

But I don't know how to connect it to the equation

Well i have an idea and here it is: So if y=2-√(2^(2)-1) y=2-√3 y(2+√3)=1 And this works for all the terms.

Well you are not supposed to use a calculator and the answer should be rounded of to nearest integer if needed.

√(2-√(2^(2)-1))+√(4-√(4^(2)-1))+√(6-√(6^(2)-1))+...+√(80-√(80^(2)-1)) How the find it's value