Recent content by matsu

Thanks for the clear expression about the Stirling approximation. I can now do the calculations myself. I appreciate your help so much!

Thanks for your reply and advice!!! Sorry, I wrote it wrong. 2.357 * 10^25 is the correct value A. I did not use Stirling's approximation, but used WolframAlpha to get the approximation below. I did the same calculation but it did not work. The number is too large for the value B. Could...

In the book "Cycles of Time" by Roger Penrose, there is a part of the explanation of entropy that I don't understand. There are 10^24 balls, half of which are red and the other half blue. The model is to arrange the balls in a cube with 10^8 balls on each edge. It also divides the cube into...

Thank you for your replying. Yes. 10^23… must be approximate value of (10^24)! But I have no idea for 10^46… I will follow your advice and start a new thread.

I don't understand the same part either, did you find out how the value 10^46,500,000,000,000 was calculated?