Recent content by max3

Yes, only that a half period would correspond to PI/4 and not PI/2 as you state since in my case PI/2 is swept in 1 full cycle. Many thanks.

That's what I figured but many have contradicted me in saying that the angular velocity is 2PI*f irrespective of the pedal NOT sweeping through 2PI. Many thanks for your feedback.

well the mechanism itself is the lower half of a pedal operated sewing machine. you may think of it as a four-bar linkage or a 'double crank'. while the upper flywheel rotates through 2pi, the pedal (connected by a rod) does not. I am given the frequency of operation of the pedal and need to...

So I've got a pedal which sweeps through pi/2 in 1 complete cycle (frequency is known). Is its angular velocity (pi/2)*f or 2pi*f just the same? (considering that it doesn't sweep through 2pi but pi/2)