Recent content by mbphysics

Is there a simpler way to solve this that I'm missing? In my practice book it is only a level 2 problem (out of 3) but it seems very complicated

I used t=20/v0cos30 and plugged that into t in the equation: vfy=v0y+ayt so it becomes vfy=v0y+ay(20/v0cos30) Then I found vfy to be (v0y2-(2*-9.8*5))1/2 and plugged that whole thing into the vf=vo+at formula. So: (v0y2-(2*-9.8*5))1/2=v0y+(-9.8)(20/v0cos30) That way the only variable is v0y...

Homework Statement A ball is thrown upward at an angle of 30degrees to the horizontal and lands on the top edge of a building that is 20m away. The top edge is 5.0m above the throwing point. How fast was the ball thrown? Homework Equations x=v0t+(1/2)at2 vf2=V02+2ax vx=v0cosθ vy=v0sinθ The...