Recent content by mcguiry03

If you are on site and you only can get the weight per unit length of cable, the distance between 2 points and the difference in elevation of the said 2 points. How can I solve for the location along the cable for the lowest sag and the tensions exerted at the two points?

what is my working equation so i can arrive at the sum of squares identity?

[SIZE="5"] it is a sum of squares in anova(analysis of data). how can i derive this equation?tnx..

prove that μ=αθ and σ^2=αθ^2 μ = E(X) ...= ∫(x = 0 to ∞) x *(1/(θ^α Γ(α))) x^(α-1) e^(-x/θ) dx ...= (1/(θ^α Γ(α))) ∫(x = 0 to ∞) x^α e^(-x/θ) dx ...= (1/(θ^α Γ(α))) ∫(t = 0 to ∞) (tθ)^α e^(-t) * (θ dt), letting t = x/θ ...= (θ/Γ(α)) ∫(t = 0 to ∞) t^α e^(-t) dt ...= (θ/Γ(α)) Γ(α+1)...

i keep on searching the internet about this type of distribution and i am not an english speaking person that is why i hardly understand what they say... i just wanted to answer this bcos it is a challenge problem for an extra points... the problem is, we skip this topic bcos we can not finish...

tnx sir

Homework Statement prove that, for gamma distribution μ=αθ σ^2=αθ^2 for exponential distribution μ=θ σ^2=θ^2

[SIZE="5"]μ=αθ σ^2=αθ^2 can someone show me how to prove that the mean and variance is equal to what is at the top... tnx a lot...:biggrin: