Recent content by mdxod

1/Ceq = 1/6 + 1/3 --> 1/6 + 2/6 = 3/6 3/6 = 1/2 = 1/ Ceq... to find Ceq flip --> Ceq = 2uF

Yep, that's why me and Doc Al were stuck...thats the answer we both got, and it is marked as wrong.

Haha, yeah i mean i finished all of the other problems and only bothered with this because i wanted my 5 points. yes i already did email my professor so let me see what he says, maybe he can give me the points anyways. It just seems ridiculous that it would reject almost every answer i came up...

Doc Al, hope you don't mind, sent you a PM

checked many times =/ i have no idea what's going on. Have two friends who had similar numbers and their answers came out to be .00XXXXX this is frustrating lol. is there any other techniques i could use? I mean i tried to keep everything in variable form before plugging in (as this is usually...

Doc Al, you are getting -.000438 m or simply taking its magnitude: .000438 meters? im putting it in, its wrong.

Thanks Doc Al, Ok SO...just to clarify i am using |q| magnitude of the charges because i changed that sign... but rearranging everything i have wrote for D...i should be having (without plugging in numbers yet) that: D = \sqrt{(d^2 * q2)/ (2*q3*(cos27)^3)} - d where i am using |q2| and |q3|...

any way to provide the diagram?

dont you need the physics GRE as well? I would think a institution like yale requires it...actually almost sure that all of them require it.

Homework Statement http://classes.uleth.ca/200503/phys2000a/private/ass02sol_files/image002.gif With \theta = 27 degrees, d = .015m, q2 = 6.4 *10^-19, q3 = q4 = -4.8 *10^-19. Problem states: Find the distance D between the origin and particle 2 if the net force on 1 due to the others is...

Not necessarily, there are students (in US) who apply to "reach" schools, just to see if they can make the cut for the interview. Now is a school has an average gpa acceptance rate of 3.6, and an average MCAT rate of 34...you can be sure there are going to be people who apply with 3.3 GPA's and...