Recent content by me189

thx a lot! i understand the case now^^

i understand that the force required is (dm/dt)v but in the formula P = Fv, v means the velocity of sand when the force is applied, isn't it? However, the velocity of the sand bit is changing when the force is applied. The initial velocity of the sand bit (when it is drop on the conveyor) is...

But is applying P = Fv right? for P = Fv, the v basically implys displacement over time, which is the average velocity of the sand during acceleration , isn't it? but at the instant that the sand drops on the conveyor, the velocity must be smaller than the velocity of the conveyor. Then it seems...

sand is pouring on a conveyor belt in a rate of rate of dm/dt kgs-1 if the velocity of the conveyor belt is v ms-1, what is the power needed to run the conveyor belt. My friend arrived at his answer in this way F = dp/dt = d(mv)/dt = v (dm/dt) N Power = Fv = (dm/dt)v2 Watts...