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Graduate Diagonalizability dependent on nullity and inner product?
Hello everyone! I am doing some work involves proving that a matrix A (A=U(V^T)) is diagonalizable. In this situation, U and V are non zero vectors in R^n. So far, I have proven that U is an eigenvector for A, and that the corresponding eigenvalue is the inner product of U and V ((U^T)V)...- meboxley
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- Inner product Product
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- Forum: Linear and Abstract Algebra