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Find load P supported by cables at 25° and 55° angles with 1860 N load Q
What I did was split the problem into two separate summations based on x & y coordinates: Tcos(25) - Tcos(55) - Px = 0 Tsin(25+Tsin(55) +Py - Q = 0, Where Q = 1860 I initially got an answer of 2391N, but it keeps marking me wrong for said answer. This is the free body diagram, (the previous...- MecEngPterois
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