Recent content by mechi

I've attached the figure... hopefully will be understandable. Here is the equation: Vt=Vab=7.44 Rx=600 Vx=7.5 Vx=(Vt*Rx)/(Rt+Rx) Therefore, Rt=-4.8 ohms Can be negative?

So... here again... Rt ----<><>----a---- | | O V=7.5 <> R = 600 | <> | | -------------b----- - I=V/Rt = 7.5/Rt - Knowing that Vab = Vt = 7.44 - Plug 1st formula into: I = V/(Rt+R) and...

Thanks! Well... I'm just starting my course and I'm not that good at electrical stuff. The scheme might be like this: R = 600 -----<><><>------ a | O V = 7.44v Voc= 7.5v | ------------------- b Being: O = V (voltage source) and <><><> = R (resistor), Voc...

I have this question: A DC source has an open circuit voltage of 7.5 volts across its output terminals. the output voltage falls to 7.44 volts when a 600 ohm precision resistor is connected to the output. draw the TEC (Vt, Rt) of the source, showing all values. also show the calculations to...