Recent content by meher4real

Not at all ! I really appreciate your time and efforts to help me out with the problem, can't thank you enough, i was literally lost but It's a matter of time for me because your process takes too long to find the solution. As i said before I'm on rush and I'm working on the last problem rn.

I found Energy required to heat paper = 0.40 J number of photons required = 1.612x10^18 photons

huh you're right, weight/1cm^2

weight x 1 cm^2 ?

What's wrong with weight 80x10^-3kg ?

g to kg isn't 10^-3 ? - N(inter)=5.6x10^18 x 180 x (1-e^(-(0.32x0.1x10^-3)) = 3.23x10^16 photons - E(abs) = N(inter)xE(photon) = 7.8 x 10^-3 J

The rest is ok ?

i used the thickness of the paper which is 0.1 mm ?! you said that is 1 mm can you explain why ?

- N(inter)=5.6x10^18 x 180 x (1-e^(-0.32x0.1x10^-3)) = 1.03x10^13 photons - E(abs) = N(inter)xE(photon) = 2.50 x 10^-6 J - Energy required to heat the paper : Q=m x Cp x T = 80x10^-3kg x 1.34 J/kg x 233° = 24.97 J - Number of photons required : 24.97/2.42x10^-19 J = 1.032x10^20 photons

By the way, is N found is the absorption energy ? is it the right result for part 2 ?

Thank you Kuru ! I'll be back with the results.

T° increase

Understood ! Must expose it to heat, means must absorb energy ?

Sorry for the delay i was at work ! Thank you for your time Kuru, but as i said before I'm a little confused because i don't know an equation that needs CP? plus i find some problems understanding some scientific sentences, I'm trying my best by using different equations to solve it but still no...