i did the following:
0 ≤ σ ≤ 6
σ^2 dσ= σ^3 /3 = 72
0 ≤ q ≤ 2π
dq= q = 2π
arctan 7/√50 ≤ Φ ≤ π
sinΦ dΦ= -cosΦ= 1+cos(arctan 7/√50 )
then i multiply them
(1+cos(arctan 7/√50 ))*2π *72=773.8884482
but when i enter it it gives me that it is wrong
hi all
how can i find the volume of the solid that lies within the sphere x^2+y^2+z^2=36 , above the xy plane, and outside the cone z=7sqrt(x^2+y^2) .
your help is very much appreiated