Recent content by michael892

show that < \frac{mv_{x}^{2}}{2}> \equiv s\int_{-\infty }^{\infty} \frac{mv_{x}^{2}}{2} \rho (v_{x}) dv_{x}=\frac{k_{B}T}{2} im stuck

i know i had to calculate surface integral but i didnt have multivariable calculus yet

Given is vector field \overrightarrow{C}(\overrightarrow{r})=r calculate flux \Phi =\int_{S} \overrightarrow{C}\cdot d\overrightarrow{A} through sphere S with beginning in [0,0,0] and r=1