Recent content by Micky1964

Someone just pointed out to me my rather obvious mistake...When I subtract the 65780 "all black" hands, the rest of the hands will also still include the 65780 "all red" hands, so I should subtract those as well. Funny how these things seem obvious in hindsight.

Can someone tell me where I'm going wrong here in part (d)? Answers from textbook: My attempt: Apologies for the blurry photo.

Thank you for replying. I can see that makes sense now. So the best approach with these types of problems is to treat each situation separately? ie. find how many ways you can have 2 girls and 1 boy, then find how many ways you can have 3 girls and 0 boys, then add the 2 figures? Mick

Hi all. I'm doing a counting/probability problem here. I can see how the correct answer for part b is arrived at by counting the number of combinations for "2 girls" then counting the number of combinations for "3 girls" , and adding these results. But I've attached my first way of approaching...