microdosemishief's latest activity
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Mmicrodosemishief replied to the thread Electric field due to arc shaped thin rod.I just read the textbook answer but I want to know why my answer is wrong and not just a different method to the same answer
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Mmicrodosemishief replied to the thread Electric field due to arc shaped thin rod.R
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Mmicrodosemishief replied to the thread Electric field due to arc shaped thin rod.Yes and dE = kdQ/r^2 so the denominator is r^2 where r = Rcos(θ) squared, because dE_x is Rcosθ distance away
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Mmicrodosemishief replied to the thread Electric field due to arc shaped thin rod.I wrote that in my question
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Mmicrodosemishief posted the thread Electric field due to arc shaped thin rod in Introductory Physics Homework Help.My attempt: due to symmetry along x-axis, net E is only along x^hat. dQ = λ dl = λ (R dθ) for each dl, the x component of distance from...
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Mmicrodosemishief reacted to Gavran's post in the thread Change in Displacement Formulation with
Like.
Both expressions for Δx and are only valid for the case where t1=0. -
Mmicrodosemishief reacted to kuruman's post in the thread Change in Displacement Formulation with Like.
Sure, but if the velocities and the times are known, it would be more sensible (and easier to remember) to write this equation in the...
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Mmicrodosemishief reacted to Herman Trivilino's post in the thread Change in Displacement Formulation with Like.
Who wrote that homework statement? First of all, it doesn't ask for a response. Secondly, displacement equals change in position. Change...
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Mmicrodosemishief reacted to PeroK's post in the thread Change in Displacement Formulation with Like.
The two calculations have a different initial velocity. Your initial formula should be: $$x = (v_0(t_2) + \frac 1 2 at_2^2) - (v_0(t_1)...
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Mmicrodosemishief posted the thread Change in Displacement Formulation in Introductory Physics Homework Help.Assuming initial displacement is zero, if x = v₁(t) + ½a(t)², why isnt Δx = x2-x1 = (v₁(t2) + ½a(t2)²) - (v₁(t1) + ½a(t1)²) = v₁(t₂ -...
