Recent content by mikbear
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Series Test for convergent and divergent
Oh. thanks for the tip. I gona try it rite now. Thanks- mikbear
- Post #6
- Forum: Calculus and Beyond Homework Help
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Series Test for convergent and divergent
I made a mistake in the question its suppose to be power of n Ʃ √n/(ln(n))^n from n=2 to ∞ I have learned root test, integral test, comparison and limit test. however I do not see how these will help solve this question.- mikbear
- Post #4
- Forum: Calculus and Beyond Homework Help
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Series Test for convergent and divergent
Homework Statement Ʃ √n/(ln(n))^2 from n=2 to ∞ Homework Equations Series Test for convergent and divergent The Attempt at a Solution I tried doing ratio test and gotten [√(n+1)*(ln(n))^n] / [(ln(n+1))^(n+1) * √n] to find the limit, do...- mikbear
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- Convergent Divergent Series Test
- Replies: 5
- Forum: Calculus and Beyond Homework Help
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Surface Area of Revolution about x axis
Homework Statement x^2 + (y - 2)^2 = 1 The hint given by the question was to split the function into 2Homework Equations Surface Area about x axisThe Attempt at a Solution So i did this. (y - 2)^2 = 1 - x^2 y = √(1 - x^2) +2 and y = 2 - √(1 - x^2) The range I calculated when...- mikbear
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- Area Axis Surface Surface area
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Undergrad Series Test for convergent and divergent
Hello. I.m struggling to understand how to test for convergent and divergent. ∞ Ʃ (n/(n+1))^(n^2) n=1