Recent content by militant07

anyone?

vx = vcos(theta) vy = vsin(theta) vyh (vy halfway up) = sqrt(0.5)*vy vh (v halfway up) = sqrt(vx^2+vyh^2) = sqrt(vx^2+0.5vy^2) vm (v at max height) = vx vx = vh/2 = sqrt(vx^2+0.5vy^2)/2 vx^2 = (vx^2+0.5vy^2)/4 0.75vx^2 = 0.125vy^2 vy/vx = sqrt(6) theta = arctan(sqrt(6)) = 67.7923457...

1. Homework Statement The speed of projectile when it reaches its maximum height is one it half speed when it’s half maximum height. What is initial projection angle of the projectile? 2. Homework Equations I know it has been asked several times but no one give the answer with...