Recent content by mnvaughn

I had a test recently and one of the problems was pretty basic. It gave you a table with the voltages at the gate, source, and drain of the device. Vt (Threshold voltage) was also provided, which was +1V. From there we were supposed to find Vgs, Vov(Overdrive voltage), Vds and the region of...

NVM I got it. So my mistake was that since Vout is -20 and outside the linear range of the op-amp then Vout is -15. From there I did KCL at the Vn node with the new Vout. (Vn-10)/5K + (Vn+15)/10K = 0 Vn=5/3 From there I did KCL at the output Vout: (-15-5/3)/10K - 15/10K = Iout Iout=-3.167 mA

Ok so I instead I did Vout=(-Rf/Rs)*Vs So (-10K/5K)*10 Vout=-20 But since Vout is still not with the linear range of the power rails, isn't Vout=15?

Homework Statement The problem is gives an ideal op-amp and wants me to find the output current of it. Here is a picture of the problem. http://i.imgur.com/NfO6q.png Homework Equations vp=vn in=ip=0 The Attempt at a Solution So what i did is take KCL at the Vn node...

WOW. I'm SOOO STUPID. I did that exactly and i got it. Thanks that problem even stumped my professor in class. Thank you soooo much

what would be your suggestion to go from here then? Do i not use a test source? because i really don't know any other way to solve it then.

if it was that simple then why isn't the answer just 1? I'm really confused on why you disregard the voltage at the bottom. Underneath the 1ohm resister is not ground but another voltage which is 2i0.

But isn't there a voltage at the bottom too? so it i0=v1/2i0?

Homework Statement The problem wants me to find the equivalent resistance at the terminals. Here is the circuit plus some of my work. The Answer according to the teacher is C. http://i.imgur.com/JaW7f.jpg Homework Equations The Attempt at a Solution As seen from my work, I added...