Recent content by momu

Nevermind haha

A circular disk of radius r is used in an evaporator and is rotated in a vertical plane. It is to be partially submerged in the liquid so as to maximize the exposed wetted area of the disk. show that the center of the disk should be positioned at height r/sqrt(1+pi^2) ok i absolutely know how...

F=0 mg-fB=0 m=p * Vs (volume of sphere)/2 Know for the volume i have 4/3pi(R^3-r^3)

no its the same equation just canceled out the g. but you Its the same V

An empty hollow sphere of inner radius r, outer radius R and density p floats so that exactly one half is submerged in a fluid of density pf. a.) if p/pf is =3 what is the ration of r/R. ok well mg=pVg m=pV/2 V=4/3pi(R^3-r^3) m=p(4/3pi(R^3-r^3) I don't know where to go from here...