Morbert's latest activity

So you're saying Ma's physics is right and he just misspoke? When he said "This can be seen by rewriting Eq. (1) in the basis of Bell...

Photons 2 and 3 are not initially entangled, as can be seen by tracing 1 and 4 out of the initial state (equation (1), or equation (2)...

So you're saying that, when Ma says "This can be seen by rewriting Eq. (1) in the basis of Bell states of photons 2 and 3" yielding (2)...

"This can be seen by rewriting Eq. (1) in the basis of Bell states of photons 2 and 3" -- Ma Ma says (1) can be written in the basis of...

👍fixed

Show me where Ma says that. You'll find it difficult since Ma explicitly says [1] can be rewritten as [2]. You're presenting your basic...

So far I haven't written any paper about entanglement swapping or anything like that, but after this discussion maybe I will. (In this...

If it was the latter there would be no minus signs.

What you mean to say is $$\begin{aligned} |\Psi^{-}\rangle\langle\Psi^{-}|_{12} \otimes |\Psi^{-}\rangle\langle\Psi^{-}|_{34} \neq...

PS to tie my last post to Bohmian mechanics you could presumably include detector and environmental degrees of freedom so the states...

As the conversation has continued I'll post here. In Ma's actual experiment, the BiSA apparatus is interpreted as performing a...

I may save my responses to @PeterDonis for that thread as they are about the experiment in general rather than a Bohmian accounting.

Two points here: i) A run where no swap is attempted will leave 2 entangled with 1 and 3 entangled with 4. But a run where a swap is...

The less important issue: The state of A does change as it passes through the PBS The polarization degree of freedom becomes correlated...

It's common in consistent histories literature, where you are often chaining many projectors together. See e.g. equation (2) in...