Recent content by Mori

Multiply it by sin(30) and multiply 7.88 again by cos(30) = (6.82 N, -3.94 N) Turn the 6uc into vector components. = (-9.34 N,0) Add the two vectors = (-2.52, 3.94) Use pythagorean theorem on it = 4.68 N Arctangent to find direction= -57.4 Degrees 4.68 N, 57.4deg S of E

4.68 N, 57.4deg S of E Got that after various tries, done?

I did these, what did I do wrong? Multiply it by sin(30) and multiply 7.875 again by cos(30) = (6.82 N, 3.94 N) Turn the 6uc into vector components. = (-9.02 N,0) Add the two vectors = (-2.2, 3.94) Use pythagorean theorem on it = 3.27 N Arctangent to find direction= -60.809688481761 degrees...

I got 34.6456i, 36.68 deg. S of E, did I get it? :D

Oh, sorry xD I might've typed it wrong,or I'm just kinda dumb.

6uc vs. -5uc = -0.0902135052958669(Attractive) -7uc vs. -5uc = 0.07875 N(Repulsive) How do I use these in trigonometry?

Okay, I'll go find each one acting on it, gimme a sec :D

Homework Statement Three charged objects are placed as shown. Find the net force on the object with the charge of -5uC Diagram:[/B] http://imgur.com/xHGHGbd Homework Equations No idea what to do as far as steps go, I don't know how to start :([/B]The Attempt at a Solution None so far.