Recent content by Mr Smailes

Equate to XE/2=XE/2

Can you show that?

To be honest this has confused me further now, I am really not sure where I am going with these equations for a 1 mark question there must be a simpler way to visualise and understand this problem

E/2 = 1/2k(x/2)^2 and E = 1/2kx^2

E/2 = 1/2kx^2

KE and PE will add together to equal the total energy

So at the halfway point?

The same amount?

They will be lower then the maxima when they are equal, it will be at some point between the max amplitude and the equilibrium position

The maximum kinetic energy must be equal to the maximum potential energy presuming all of the potential energy is converted to kinetic

Maximum potential energy is at either end where K.E is zero. In the middle would the K.E not be maximum and the potential energy be 0?

Max P.E is equal to minimum K.E and vice versa

The PE increases with displacement but I am still unsure of your first question in how does PE compare with max PE?

Thanks for all your help I now understand the potential energy is increasing from the equilibrium position and the kinetic energy is decreasing from the equilibrium position where it is max. So they will be equal at some point between the equilibrium position and the max amplitude but how do I...

I'm confused due to there being two springs so would the PE for one not be maximum when it is minimum for the other?