Recent content by MrAAK

No worries, I called the US defence department, surprisingly helpful to an Irishman (real one, not American). Cheers.

Hey guys, I am currently working on a uni MATLAB group project for blast radius, thermal radius etc. Apparently these formula are the best possible to use: r_thermal = Y^0.41 * constant_th r_blast = Y^0.33 * constant_bl r_radiation = Y^0.19 * constant_rad But can anybody tell me what...

I think I 70%'d the maths and today, if I left that physics exam with less than 90%, I would not be amused. Well, as long as its above 70% I am happy. Thank you al for your help. It was invaluable!

Yeah, sorry, that's what I meant to say.

You sir, have saved me a sleepless night. I'm smoking this one for you(The manual)! I have been panicking for about 3 hours, I tried nested before and it didnt work? Bizarre! Thanks! (I emailed my Professor at 11pm, probably shouldn't have done that), oh well...exam stress etc. Thanks guys!

Thats an idea, ill give that a go, two secs.

Yeah, I know, for complex numbers etc, but this is just a simple bedmas operation under the radical. It won't accept more than the first digit under the radical. (so if its a negative X negative etc, its no use).

Mainly for reasons of long winded decimal points, I would have to use just 3 decimals in order to maintain my time frame. (Also accuracy). It's easy with 100 under the radical, for an answer I should be getting of 10. But when I am in the exam, its going to be 4.798687692 etc...

Hi Quantum, thanks for your reply, I have the manual here with me, I tried that. I pressed root 4^2= ANS popped up then I tried the rest. Math error. Can't square negative numbers.

Homework Statement Hello, I have to use the HP 10s calculator at my university, I have been used to my modern casio for the last 4 years but I have a problem. The square root symbol when pressed does not allow for continual calculation, such as when I am using the quadratic formula. It seems to...

Brief hello here, I am studying foundation physics to start an applied physics MPhys. I will be needing help and hopefully one day giving it back!