Recent content by mrose94

Hello. My attempt at the solution is as follows: l = 160m Q= 300 ls-1 R= p2/p1= 6+1.01/1.01 = 6.94 (2dp) d = Unknown Pressure drop = 0.3 Bar 0.3 = 800*160*300^2/6.94*d^5.31 0.3 = 1.152x10^10/6.94*d^5.31 0.3 ( 6.94*d^5.31) = 1.152x10^10 6.94*d^5.31 = 1.152x10^10/0.3 d^5.31 =...