Recent content by mrowcow

Thank you so much! I understand now. The hints about the sign of cos and sin were super helpful. You are amazing people.

If the cosine is negative, then the angle is between 90 and 270 degrees. So the angle is 213.7 or 146.7 degrees? Was I completely off track originally then? I still feel like my original approach makes sense... except for the fact that your point makes my original answer definitively wrong. Thanks!

Homework Statement Vectors A and B have scalar product -6.00 and their vector product has magnitude 4.00. What is the angle between these two vectors?Homework Equations A \dot B = ||A|| ||B|| cos θ and A \cross B = ||A|| ||B|| sin θThe Attempt at a Solution Then I reasoned that tan(θ) = -4/6 so...