Recent content by mrphobio

Homework Statement A 293g block is placed on a spring with a spring constant of 161N/m, compressing it 42cm. What height does the block reach when it is launched?Homework Equations Eel=1/2*k*x2 Eg=mgh The Attempt at a Solution Eg=.293*10*.42=1.2306 1.2306=1/2*161*x2 1.2306=80.5x2 .0153=x2...

Well. There we go it worked. I have not a clue where I got that 877. Sometimes another pair of eyes helps a lot haha

Homework Statement A 12 kg box slides across the floor with an initial velocity of +8.4 m/s. It comes to a stop after sliding +13.8 m. How much friction was present? Homework Equations f=ma v^2=v(o)^2+2ad The Attempt at a Solution I did the ''v^2" equation to find out what the...

Yah and it helped that you guys both walked me through the steps rather then just doing it for me

i did the 70kg times the 20 (because it was the maxium occupancy). and then added the answer to that to 540kg to get the total down force. I converted it to Newtons then subtracted the up force (32471) from the down force. With that, I did F=Ma and got the answer. hopefully that made sense haha

Yah i got number 2. I was able to figure it out all by myself :D. Drawing things out makes it sooooo much easier.

Sick! i can't thank you enough. I would of got none of the equations right if it weren't for this. Website crashed again (probably because of all the kids doing homework last minute) but ill get it in as soon as it is up! thanks again and good night.

115.73 Now is this when i plug into cos? cos(28)=115.73/x (with x=hypotinus)

Fx-Ff=ma... So i know Fx-68=12.9*3.7

If the sum of the forces in the x direction equal mass time acceleration, then that would mean 12.9*3.7=47.73. But that's less then the friction.. so wouldn't that mean that it is not moving?

okay. So i want to find the force that is parrelel to the ground (other then friction). So to use one of the sin, cos, tan i need another side to the triangle. Would it be the 14.9kg that is pushing the lawnmower down?

So sin? because this is where i am confused. I don't know if i want to find the hypotinus or the just left to right force

Now to number 3. I would do tan(28)=129/fx correct? Then fx-68 to find the answer?

The website where i do my homework just crashed. Ill try it once it gets back up. Yah thanks very much. That is what my teacher is lacking, he shows rather then explaining on why it works that way. i apperciate your guys help to much

Alrighty. So 50 is the force right? and as for the mass, is it 65kg? or am i just making weird connections?