Recent content by msmmpts

simon,according to the exercise the final result does not contain any hyperbolic terms.

If I could get rid of cosx from numerator,then we could have substituted tan(x/2)=t dx=2dt/1+tsquare cosx=1-tsquare/1+tsquare. I tried dividing num&denom by cosx but no good.

it is "acosx"..a is the parameter

Homework Statement solve ∫log(1+acosx) by differentiation under integral sign (limits are 0 to ∏) Homework Equations The Attempt at a Solution =∫(1/1+acosx)cosxdx(by leibinitz by differentiating partially WRT a. Then how do I proceed,can anyone show me all the steps of...