Recent content by mt05

yes, thank you. F = Fg + KE F = (4)(9.81) + 1/2(4)(2^2) F = 47.24 N (so this is required force that block A must pull in order to move 4kg box at 2m/s) I'm struggling to think of finding the force that an unknown mass has.

Homework Statement Block A is traveling down an incline plane of 35 degrees at 2m/s. It's pulling a 4kg block with a pulley and rope. Coefficient of friction is.12. How heavy must block A be ? Homework Equations F=MA F = WsinΦ + μWcosΦ mgh = 1/2 mv^2 + WD to overcome friction Vf^2 = u^2 +...

ah yes that makes sense. Thanks for the help!

hmm sorry, I still am not following dh = 2628.718 (this is the amount of heat made by the boiler to make 5600kpa and 472 degrees Celsius of steam) boiler running at a 82% efficiency. 18% of heat from the fuel is lost correct? So why couldn't I take 2628.718 and multiply that by 1.18 to...

1) Feed water enters a boiler at 172.52 degrees Celsius. The boiler produces super heated steam at 5600kpa and 472 degrees Celsius. The boiler efficiency is 82%. Find the Heat required by fuel. 2) I interpolated the value given for feed water and super heated steam. h@5600kpa 472 degrees...

1) see pdf for question 2 I'm unsure how to calculate the force at the fulcrum since its not in equilibrium. I thought maybe i would add the two forces together, but that doesn't seem right. 2) so this question asks for what forces need to be applied at points A and B and i understand...

hey everyone! I think this question can probably be solved using a constant acceleration formula, but since we are doing the momentum and work units in class i figured i was suppose to use those formulas to solve my question. anyways here it is : Paul lives on the sixth floor of an apartment...