Recent content by mundane
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
Should this be cone in spherical coordinates? If so, how would it be set up? I am absolutely lost trying to find where these functions intersect. Please help!- mundane
- Post #19
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
If anybody can still help me here... Does this method work for my problem? It is a sphere being cut by a sheet... If so, how can I set up the intersection? I am stuck at 2^x+2^y-1=sqrt(-x^2-y^2+100)- mundane
- Post #18
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
Would it be (4-x^2-y^2) - (x^2+y^2-4) which is -2x^2-2y^2 +8?- mundane
- Post #17
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
Awesome... Before you go, could you just show how I should subtract the two surfaces for the inner function? I have gotten this far on my own problem now, just need that last step which I am unsure of...- mundane
- Post #16
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
I just graphed both surfaces and it looks like two equally sized paraboloids, one upside down and the other right side up... How do I know which is larger? Also, why do we want that specific order for the integral? Is y supposed to be fixed for as long as possible because we made it have...- mundane
- Post #14
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
Okay, would it be ∫(4−x2−y2 to x2+y2−4)∫(-2 to 2)∫(-√4 - y to +√4 - y) ... dxdydz ? that "..." is another place where I'm not sure what belongs...- mundane
- Post #12
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
Or do I have to plug -2 and 2 in for one of them? If I made the limits for y -2 and 2, how would that problem be solved? Just by plugging in..?- mundane
- Post #10
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
The limits for x would be:√(4-y2) And the limits for y would be : √(4-x2) Is that right?- mundane
- Post #9
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
Sorry, 2x2+2y2=8. so x2+y2=4. Do I set something equal to zero to find an intersection? Is it y=±2 and x=±2?- mundane
- Post #7
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
Would you set them equal to each other, then move them to one side of the equals sign to make them zero? I did z=4-x^2-y^2 and z=x^2+y^2-4 so 4-x2-y2 = x2+y2-4 then 2x2+2y2=0... not sure what I would do next... Also, did I express the functions in terms of z correctly? And when you...- mundane
- Post #5
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
Thanks for the reply... Let me try this: So for the first function: z = 2x+2y-1 And for the second function: z = √(-x2-y2+100) So those are the limits in the triple integral for z? I am not quite sure what you mean by "fix z=0 so you can find points of intersection." Would you mind...- mundane
- Post #3
- Forum: Calculus and Beyond Homework Help
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M
Setting up a Triple Integral to Find Volume Enclosed by Two Functions
Homework Statement Find the volume of the region of space enclosed between the functions: 1=-z+2x+2y and 100=z2+y2+x2. The Attempt at a Solution I am not sure how to set this problem up. I think it is a triple integral, since there is a z-component. I graphed the equation in an program and...- mundane
- Thread
- Functions Integral Triple integral Volume
- Replies: 19
- Forum: Calculus and Beyond Homework Help
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M
How can calculus help us understand the time index function across the universe?
Indeed... I understand, I am just lost on how to create a function out of it...- mundane
- Post #7
- Forum: Calculus and Beyond Homework Help
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M
How can calculus help us understand the time index function across the universe?
Sorry, I thought you were actually wondering that, :P As far as I can tell, it might be a function of location in the universe against the speed at which one perceives time? That's the direction I was heading... but I am not sure of myself. If that were the case, would I get an instantaneous...- mundane
- Post #5
- Forum: Calculus and Beyond Homework Help
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M
How can calculus help us understand the time index function across the universe?
Thanks for the reply... The professor will not tell us... He is purposely being very vague, and I just need something to set up that I can then try some calculus on or talk about what would happen if calculus were done to it... He said we should get no numbers, just a vague...- mundane
- Post #3
- Forum: Calculus and Beyond Homework Help