Recent content by mynameiscosine

Oh wow. Interesting! You made me see my mistakes in understanding dynamics! I think sometimes I am too focus in looking at this problem in one angle. I kept trying to introduce the variable 't' into the problem instead. Thank you so much for taking the time to explain to me. I fully...

Oh I got what you mean now! Sorry for getting it slow! Correct me if I am wrong: Energy loss due to friction = F x d 2N x 15 = 30J Epotential + Ekinetic + Efrictional = (30 x 12) + (0.5 x 3 x 42) + 30 = 360 + 24 + 30 = 414J Am I understanding this part correctly? After...

The other equation is d = vt - 0.5at2 v is the initial velocity. But I cannot figure out how this can help me find acceleration as time is not given to me. I am sorry, how do I calculate the energy lost due to friction in this case? Thank you!

Oh I see. Can I ask you the reason why I cannot go from acceleration to velocity via integration? I actually thought that t is the same for both equations? Thank you. Which energy have I not considered into total energy? My initial thought was, Law of conservation of energy, so...

I can do this but I am not sure if I am over-complicating this. a = acceleration v = velocity a = (4-0)/t = 4/t integrate a = v v = 4 ln (t) When v = 4 ln (t) = 1 t = e^1 therefore, a = 4/e^1 = 1.4715... m/s^2 Force = m x a = 3 x 1.4715 = 4.4145... N I am not...

Hi all. I am marking GCSE paper that I did myself. There is 1 problem that I do not seems to understand. Please help me. Thank you very much. Homework Statement Daniel pulls a 3kg box up a slope from rest as shown (Attached) Given that the average friction of a slope is 2N and the speed at...