Recent content by nadavg54

umm nevermind this question. I'll try to ask about something more simple . [which help me understand my original question] lets say there are two boxes with masses m1 and m2 , m2 sits on tops of m1. and m1 let's say sits on a table . they arent moving . no friction between m1 and m2 and between...

the Newton force equations ... the two masses will slide down the slope because of forces [ gravity , friction ...] so did i get the equations right?

ok , let's say we add an additional force on mass A with the same directions as its movment[someone pushes it..], so what would be the equations now on each masses? would it be the same equations that I written plus the additional components of the new force?

i don't that true with static friction... static friction is when there arent relative motion between the two objects.. so any1 else please? thanks

no, they'll both have the same accelaration of g*sina(alpha), but here u do have friction.. so my equations arent correct?

[PLAIN]http://img221.imageshack.us/img221/541/slope.png Homework Statement two masses sliding down a slope[slope can't move] like in the attached picture. there is a static friction 'c' between the two masses. and between mass a and the slope there isn't any friction. so I am trying to...

so my equations are not correct?

I read that if you are in a spaceship orbiting Earth in a circular motion, the astronout feels weightless (meaning the normal force to the astronout is equal to zero). But according to Newton laws equations you get: and then if we assume N=0 (which is really what's happening according to my...

i read that if u r in "spaceship" that's for example has circular orbit around Earth - than u r in a zero gravity state. but from Newton law u get this equations : mMG/R^2-N=mV^2/R so from this i get that N equal MG/R^2-V^2/R and why would MG/R^2-V^2/R be zero ? no metter what?