Recent content by Nafi Khandaker

Thanks for replying. I asked someone else who has more math experience than me and he said something similar.

In this problem, Spivak shows how to derive formulas to summations. They start by showing the method for 1^2 + 2^2 + ... + n^2 as follows: (k + 1)^3 - k^3 = 3k^2 + 3k + 1 Writing this formula for k = 1, 2, ..., n and adding, we obtain 2^3 - 1^3 = 3*1^2 + 3*1 + 1 3^3 - 2^3 = 3*2^2 + 3*2 + 1 ...