Would link 3 be redundant since the position/rotation of the disk already has only 1 DoF due link 5 and the ground (link 1/joint D)? Then you have 1 DoF due to link 2 which wouldn't be connected to anything else, so a total of 2 DoF for the mechanism with one redundancy.
Am I on the right track...
I need to find the mobility of the pictured system
I have labeled the 5 links with black numbers and the 6 joints with red letters for convenienceAttempt at a solution: I know the mobility equation is M = 3(N-1) – 2(J1) – J2 + R, where N = number of links, J1 is the number of 1 DoF Joints, J2...