Okay, I think what you're trying to get at is that since it is an empty socket there is no wire for the current to flow through that part of the circuit. Meaning it becomes open so the current doesn't flow through that way. So it ends up just flowing to the bulb on its own on the left meaning...
When the bulb is removed, then the current should split evenly between the left bulb (which is bulb C) and the right bulb (which is bulb D). I understand that this would brighten bulb D and dim bulb C since they are now receiving 0.5I from the current. But, that should have no effect on the...
I understand that removing bulb E will cause the equivalent resistor to change in the circuit. This change will cause the current across the circuit to change (which will either brighten or dim the bulbs).
I found that R_eq (with E) is 1.167.
R_eq = [1 + (1/1+1)]^-1 + [1 + 1]^-1 = 1.167
I...